On Oct 28, 12:24*pm, geronimo <Jam...@grandecom.net> wrote:
> * *I am adding a 12V external *connection to my Volvo *92 740 to be
> able to run/charge the DC system on my pop-up camper, which has a 12 V
> deep cycle battery. So I got one of those three-terminal battery
> isolators. The alternator output goes to the center terminal, and the
> car battery and the pop-up battery go to the other two terminals. The
> alternator puts out abt 14 V measured with my fluke. However, each of
> the isolator diodes has about a 1 volt drop across it, so now there is
> just 13 volts available to charge either battery....at the battery
> terminals.
> * * Question is, is this going to be sufficient to keep the batteries
> topped off? I was expecting to have something less of a drop than what
> this diode isolator has, since a silicon diode junction when forward
> biased has a .6 volt drop. I have heavy gauge wire and tight
> connections, so I am sure that the voltage drop is at the diode
> junctions. I believe the alternator, which is OEM, has an internal
> regulator, and probably no way to tweak the voltage up to compensate
> for this. Do I have a problem, or not?
Read at
www.batteryuniversity.com 13.8 is needed to get to a peak,
14 is a peak voltage and works. 13 is not going to saturate cells but
will do if you use a seperate charger at home and this is just a
vaction set up. 12.8 is a fully stabilised charge, but it needs to
peak for a while at 13.8 or so. That is a hard load on an alternator
to run it as a charger, an easy way to burn one out is what you
propose.