R
rndthought
First, this is born out of a "mental exercise" between the parts boys
and myself...about the merits of K&N air filter...filtering efficiency
withstanding, they are being marketed on the sole concept of CFM at the
local parts store.
How would one figure the CFM required at some RPM for an "X" liter
motor?
Would it consume "X" Liters every 2 revolutions? (4 stroke,
up/down/up/down - so one time it goes down it will be due to the
combustion stroke not intake...right?)
If:
1 liter = 0.0353 ft^3 (man, can't imagine cramming 30, 2 liter
bottles in a 1 foot cube box!)
So would this be correct? (Liter) * (RPM)/2 *(0.0353) = CFM
For a 2.3 liter motor with a Red Line of 8000 RPM:
(2.3)*(8000/2)*(0.0353) = 325 CFM
Just trying to determine if anyone really needs a K&N air filter that
claims 450 CFM (in this case) - especially since most people don't
generally drive around at the Red Line!!!
and myself...about the merits of K&N air filter...filtering efficiency
withstanding, they are being marketed on the sole concept of CFM at the
local parts store.
How would one figure the CFM required at some RPM for an "X" liter
motor?
Would it consume "X" Liters every 2 revolutions? (4 stroke,
up/down/up/down - so one time it goes down it will be due to the
combustion stroke not intake...right?)
If:
1 liter = 0.0353 ft^3 (man, can't imagine cramming 30, 2 liter
bottles in a 1 foot cube box!)
So would this be correct? (Liter) * (RPM)/2 *(0.0353) = CFM
For a 2.3 liter motor with a Red Line of 8000 RPM:
(2.3)*(8000/2)*(0.0353) = 325 CFM
Just trying to determine if anyone really needs a K&N air filter that
claims 450 CFM (in this case) - especially since most people don't
generally drive around at the Red Line!!!